What are the solutions to the equation solvefor r,f=-1r^8 ?

The solutions to the equation solvefor r,f=-1r^8 are

Find the zeros of solvefor r,f=-1r^8

The zeros of solvefor r,f=-1r^8 are

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solve for

r, f = - 1 r^{8}

r = - \frac{4 f}{2 2 - \frac{( 2 - 2 ) 4 f}{4}} + - \frac{( 2 - 2 ) 4 f}{4} i, r = - \frac{4 f}{2 ( - 2 - \frac{( 2 - 2 ) 4 f}{4} )} - - \frac{( 2 - 2 ) 4 f}{4} i

Solution steps

f = - 1 \cdot r^{8}

Switch sides

- 1 \cdot r^{8} = f

Divide both sides by

- 1

r^{8} = - f

Rewrite the equation with

u = r^{2}

and

u^{4} = r^{8}

u^{4} = - f

Solve

u^{4} = - f : u = \frac{2 4 f}{2} + i \frac{2 4 f}{2}, u = - \frac{2 4 f}{2} - i \frac{2 4 f}{2}

u = \frac{2 4 f}{2} + i \frac{2 4 f}{2}, u = - \frac{2 4 f}{2} - i \frac{2 4 f}{2}

Substitute back

u = r^{2},

solve for

r

Solve

r^{2} = \frac{2 4 f}{2} + i \frac{2 4 f}{2} :

No Solution

Solve

r^{2} = - \frac{2 4 f}{2} - i \frac{2 4 f}{2} : r = - \frac{4 f}{2 2 - \frac{( 2 - 2 ) 4 f}{4}} + - \frac{( 2 - 2 ) 4 f}{4} i, r = - \frac{4 f}{2 ( - 2 - \frac{( 2 - 2 ) 4 f}{4} )} - - \frac{( 2 - 2 ) 4 f}{4} i

The solutions are

r = - \frac{4 f}{2 2 - \frac{( 2 - 2 ) 4 f}{4}} + - \frac{( 2 - 2 ) 4 f}{4} i, r = - \frac{4 f}{2 ( - 2 - \frac{( 2 - 2 ) 4 f}{4} )} - - \frac{( 2 - 2 ) 4 f}{4} i

1 - 4 x^{2} - 4 x^{4} = 0

8 = x^{5}

- x^{3} + 2 x^{2} - x + 2 = 0

(y^{2} - 5)^{2} + 2 (y^{2} - 5) - 24 = 0

115.76 = 100 (1 + x)^{3}

What are the solutions to the equation solvefor r,f=-1r^8 ?
The solutions to the equation solvefor r,f=-1r^8 are
Find the zeros of solvefor r,f=-1r^8
The zeros of solvefor r,f=-1r^8 are