What are the solutions to the equation -x^3+2x^2-x+2=0 ?

The solutions to the equation -x^3+2x^2-x+2=0 are x=2,x=i,x=-i

Find the zeros of -x^3+2x^2-x+2=0

The zeros of -x^3+2x^2-x+2=0 are x=2,x=i,x=-i

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- x^{3} + 2 x^{2} - x + 2 = 0

x = 2, x = i, x = - i

Solution steps

- x^{3} + 2 x^{2} - x + 2 = 0

Factor

- x^{3} + 2 x^{2} - x + 2 : - (x - 2) (x^{2} + 1)

- (x - 2) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = 2, x = i, x = - i

(y^{2} - 5)^{2} + 2 (y^{2} - 5) - 24 = 0

115.76 = 100 (1 + x)^{3}

x^{4} - 8 x^{3} + 92 x^{2} - 32 x + 169 = 0

x^{4} + 5 = 6 x^{2}

- 0.2 x^{3} + x + 4 = 0

What are the solutions to the equation -x^3+2x^2-x+2=0 ?
The solutions to the equation -x^3+2x^2-x+2=0 are x=2,x=i,x=-i
Find the zeros of -x^3+2x^2-x+2=0
The zeros of -x^3+2x^2-x+2=0 are x=2,x=i,x=-i