What are the solutions to the equation 5x^3-3x+1=0 ?

The solutions to the equation 5x^3-3x+1=0 are x\approx-0.90595…

Find the zeros of 5x^3-3x+1=0

The zeros of 5x^3-3x+1=0 are x\approx-0.90595…

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5 x^{3} - 3 x + 1 = 0

x \approx - 0.90595 \dots

Solution steps

5 x^{3} - 3 x + 1 = 0

Find one solution for

5 x^{3} - 3 x + 1 = 0

using Newton-Raphson:

x \approx - 0.90595 \dots

Apply long division:

\frac{5 x ^{3} - 3 x + 1}{x + 0.90595 \dots} = 5 x^{2} - 4.52979 \dots x + 1.10380 \dots

5 x^{2} - 4.52979 \dots x + 1.10380 \dots \approx 0

Find one solution for

5 x^{2} - 4.52979 \dots x + 1.10380 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 0.90595 \dots

x^{3} + 10 x^{2} - 1625 + 18750 = 0

2 x^{3} - 4 x = 0

z, z^{3} = 1

u^{3} + u^{2} + 1 = 0

x^{3} - 14 x^{2} + 40 x = 0

What are the solutions to the equation 5x^3-3x+1=0 ?
The solutions to the equation 5x^3-3x+1=0 are x\approx-0.90595…
Find the zeros of 5x^3-3x+1=0
The zeros of 5x^3-3x+1=0 are x\approx-0.90595…