What are the solutions to the equation 27y^3-27y^2+9y-1=0 ?

The solutions to the equation 27y^3-27y^2+9y-1=0 are y= 1/3

Find the zeros of 27y^3-27y^2+9y-1=0

The zeros of 27y^3-27y^2+9y-1=0 are y= 1/3

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27 y^{3} - 27 y^{2} + 9 y - 1 = 0

y = \frac{1}{3}

Decimal Notation

y = 0.33333 \dots

Solution steps

27 y^{3} - 27 y^{2} + 9 y - 1 = 0

Factor

27 y^{3} - 27 y^{2} + 9 y - 1 : (3 y - 1)^{3}

(3 y - 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 y - 1 = 0

Solve

3 y - 1 = 0 : y = \frac{1}{3}

The solution is

y = \frac{1}{3}

x^{5} + 2 x^{3} + x - 1 = 3

x^{6} - 25 x^{4} - 16 x^{2} + 400 = 0

7 y^{3} + 17 y^{2} = 12 y

x, x^{3} + (y - 1)^{2} = 9

a, y = a^{3} + b^{2}

What are the solutions to the equation 27y^3-27y^2+9y-1=0 ?
The solutions to the equation 27y^3-27y^2+9y-1=0 are y= 1/3
Find the zeros of 27y^3-27y^2+9y-1=0
The zeros of 27y^3-27y^2+9y-1=0 are y= 1/3