What are the solutions to the equation x^4=(x-2)6 ?

The solutions to the equation x^4=(x-2)6 are No Solution for x\in\mathbb{R}

Find the zeros of x^4=(x-2)6

The zeros of x^4=(x-2)6 are No Solution for x\in\mathbb{R}

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x^{4} = (x - 2) 6

No Solution for x \in R

Solution steps

x^{4} = (x - 2) \cdot 6

Expand

(x - 2) \cdot 6 : 6 x - 12

x^{4} = 6 x - 12

Move

12

to the left side

x^{4} + 12 = 6 x

Move

6 x

to the left side

x^{4} + 12 - 6 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{4} - 6 x + 12 = 0

Find one solution for

x^{4} - 6 x + 12 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

0 = - \frac{x ^{3}}{3} + x^{2}

4 x^{2} - 2 x^{3} - 2 x^{3} - x^{4} = 0

3 x^{3} + x^{2} - 38 x + 24 = 0

x^{3} + 3 x^{2} = - x^{2} + 3 x + 7

3018 = x^{4} - x^{3} - 7 x^{2} + 9 x

What are the solutions to the equation x^4=(x-2)6 ?
The solutions to the equation x^4=(x-2)6 are No Solution for x\in\mathbb{R}
Find the zeros of x^4=(x-2)6
The zeros of x^4=(x-2)6 are No Solution for x\in\mathbb{R}