What are the solutions to the equation y^3+4y^2-25y-100=0 ?

The solutions to the equation y^3+4y^2-25y-100=0 are y=-4,y=-5,y=5

Find the zeros of y^3+4y^2-25y-100=0

The zeros of y^3+4y^2-25y-100=0 are y=-4,y=-5,y=5

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y^{3} + 4 y^{2} - 25 y - 100 = 0

y = - 4, y = - 5, y = 5

Solution steps

y^{3} + 4 y^{2} - 25 y - 100 = 0

Factor

y^{3} + 4 y^{2} - 25 y - 100 : (y + 4) (y + 5) (y - 5)

(y + 4) (y + 5) (y - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 4 = 0 or y + 5 = 0 or y - 5 = 0

Solve

y + 4 = 0 : y = - 4

Solve

y + 5 = 0 : y = - 5

Solve

y - 5 = 0 : y = 5

The solutions are

y = - 4, y = - 5, y = 5

- 4 = r^{20} - 5

3 x^{3} + 375 = 0

x = 6.9 + 9 (x - 5)^{3}

7 x^{3} + 3 x^{2} - 29 x + 11 = 0

- x^{3} + 5 x^{2} - 4 x = 0

What are the solutions to the equation y^3+4y^2-25y-100=0 ?
The solutions to the equation y^3+4y^2-25y-100=0 are y=-4,y=-5,y=5
Find the zeros of y^3+4y^2-25y-100=0
The zeros of y^3+4y^2-25y-100=0 are y=-4,y=-5,y=5