What are the solutions to the equation -0.2x^3+2x^2-4x=0 ?

The solutions to the equation -0.2x^3+2x^2-4x=0 are x=0,x=5+sqrt(5),x=5-sqrt(5)

Find the zeros of -0.2x^3+2x^2-4x=0

The zeros of -0.2x^3+2x^2-4x=0 are x=0,x=5+sqrt(5),x=5-sqrt(5)

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- 0.2 x^{3} + 2 x^{2} - 4 x = 0

x = 0, x = 5 + 5, x = 5 - 5

Decimal Notation

x = 0, x = 7.23606 \dots, x = 2.76393 \dots

Solution steps

- 0.2 x^{3} + 2 x^{2} - 4 x = 0

Factor

- 0.2 x^{3} + 2 x^{2} - 4 x : - x (0.2 x^{2} - 2 x + 4)

- x (0.2 x^{2} - 2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 0.2 x^{2} - 2 x + 4 = 0

Solve

0.2 x^{2} - 2 x + 4 = 0 : x = 5 + 5, x = 5 - 5

The solutions are

x = 0, x = 5 + 5, x = 5 - 5

x^{3} - 3 x^{2} + 3 x - 65 = 0

(x^{2} + 6)^{2} = 0

32 = 4 x^{3}

k + k^{3} = 68

z^{3} + 2 z^{2} + 21 z + 58 = 0

What are the solutions to the equation -0.2x^3+2x^2-4x=0 ?
The solutions to the equation -0.2x^3+2x^2-4x=0 are x=0,x=5+sqrt(5),x=5-sqrt(5)
Find the zeros of -0.2x^3+2x^2-4x=0
The zeros of -0.2x^3+2x^2-4x=0 are x=0,x=5+sqrt(5),x=5-sqrt(5)