What are the solutions to the equation 32=4x^3 ?

The solutions to the equation 32=4x^3 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of 32=4x^3

The zeros of 32=4x^3 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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32 = 4 x^{3}

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

32 = 4 x^{3}

Switch sides

4 x^{3} = 32

Divide both sides by

4

x^{3} = 8

For

x^{3} = f (a)

the solutions are

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

x = 38, x = 38 \frac{- 1 + 3 i}{2}, x = 38 \frac{- 1 - 3 i}{2}

38 = 2

Simplify

38 \frac{- 1 + 3 i}{2} : - 1 + 3 i

Simplify

38 \frac{- 1 - 3 i}{2} : - 1 - 3 i

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

k + k^{3} = 68

z^{3} + 2 z^{2} + 21 z + 58 = 0

(x - 7)^{3} = 13

(x^{2} - x - 2)^{2} = 0

x, x^{3} + y^{2} = 1

What are the solutions to the equation 32=4x^3 ?
The solutions to the equation 32=4x^3 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of 32=4x^3
The zeros of 32=4x^3 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i