What are the solutions to the equation (x^2-x-2)^2=0 ?

The solutions to the equation (x^2-x-2)^2=0 are x=2,x=-1

Find the zeros of (x^2-x-2)^2=0

The zeros of (x^2-x-2)^2=0 are x=2,x=-1

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(x^{2} - x - 2)^{2} = 0

x = 2, x = - 1

Solution steps

(x^{2} - x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{2} - x - 2 = 0 : x = 2, x = - 1

The solutions are

x = 2, x = - 1

x, x^{3} + y^{2} = 1

(1 - y) (3 - y) (6 - y) = 18

(s^{3} - s^{2} + s - 1) = s^{2} + 3 s + 4

8 x^{4} = 6 x^{3}

x^{3} + 7 x^{2} + 2 x + 14 = 0

What are the solutions to the equation (x^2-x-2)^2=0 ?
The solutions to the equation (x^2-x-2)^2=0 are x=2,x=-1
Find the zeros of (x^2-x-2)^2=0
The zeros of (x^2-x-2)^2=0 are x=2,x=-1