What are the solutions to the equation 2(x+6)(16x^2-25)=0 ?

The solutions to the equation 2(x+6)(16x^2-25)=0 are x=-6,x=-5/4 ,x= 5/4

Find the zeros of 2(x+6)(16x^2-25)=0

The zeros of 2(x+6)(16x^2-25)=0 are x=-6,x=-5/4 ,x= 5/4

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2 (x + 6) (16 x^{2} - 25) = 0

x = - 6, x = - \frac{5}{4}, x = \frac{5}{4}

Decimal Notation

x = - 6, x = - 1.25, x = 1.25

Solution steps

2 (x + 6) (16 x^{2} - 25) = 0

Factor

2 (x + 6) (16 x^{2} - 25) : 2 (x + 6) (4 x + 5) (4 x - 5)

2 (x + 6) (4 x + 5) (4 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or 4 x + 5 = 0 or 4 x - 5 = 0

Solve

x + 6 = 0 : x = - 6

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

Solve

4 x - 5 = 0 : x = \frac{5}{4}

The solutions are

x = - 6, x = - \frac{5}{4}, x = \frac{5}{4}

x^{2} (x - 2) - 4 (x - 2) = 0

(1 + x)^{3} = 1.3

x^{6} - 3 x^{2} - 2 = 0

3 x^{3} + 20 x^{2} - 7 x = 0

(x^{3} + 3 x^{2}) - (9 x + 27) = 0

What are the solutions to the equation 2(x+6)(16x^2-25)=0 ?
The solutions to the equation 2(x+6)(16x^2-25)=0 are x=-6,x=-5/4 ,x= 5/4
Find the zeros of 2(x+6)(16x^2-25)=0
The zeros of 2(x+6)(16x^2-25)=0 are x=-6,x=-5/4 ,x= 5/4