What are the solutions to the equation 4w^4+40w^2-44=0 ?

The solutions to the equation 4w^4+40w^2-44=0 are w=1,w=-1,w=sqrt(11)i,w=-sqrt(11)i

Find the zeros of 4w^4+40w^2-44=0

The zeros of 4w^4+40w^2-44=0 are w=1,w=-1,w=sqrt(11)i,w=-sqrt(11)i

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4 w^{4} + 40 w^{2} - 44 = 0

w = 1, w = - 1, w = 11 i, w = - 11 i

Solution steps

4 w^{4} + 40 w^{2} - 44 = 0

Rewrite the equation with

u = w^{2}

and

u^{2} = w^{4}

4 u^{2} + 40 u - 44 = 0

Solve

4 u^{2} + 40 u - 44 = 0 : u = 1, u = - 11

u = 1, u = - 11

Substitute back

u = w^{2},

solve for

w

Solve

w^{2} = 1 : w = 1, w = - 1

Solve

w^{2} = - 11 : w = 11 i, w = - 11 i

The solutions are

w = 1, w = - 1, w = 11 i, w = - 11 i

- a^{3} + 4 a^{2} - 5 a + 2 = 0

x^{5} - x^{4} - 9 x^{3} = 0

3 x^{3} - 5 x + 2 = 0

(3 x - 1)^{2} x (x - 3) = 1

z^{3} - 3 z - 3 = 0

What are the solutions to the equation 4w^4+40w^2-44=0 ?
The solutions to the equation 4w^4+40w^2-44=0 are w=1,w=-1,w=sqrt(11)i,w=-sqrt(11)i
Find the zeros of 4w^4+40w^2-44=0
The zeros of 4w^4+40w^2-44=0 are w=1,w=-1,w=sqrt(11)i,w=-sqrt(11)i