What are the solutions to the equation (-2x^2+5x+3)(3x-2)=0 ?

The solutions to the equation (-2x^2+5x+3)(3x-2)=0 are x=3,x=-1/2 ,x= 2/3

Find the zeros of (-2x^2+5x+3)(3x-2)=0

The zeros of (-2x^2+5x+3)(3x-2)=0 are x=3,x=-1/2 ,x= 2/3

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(- 2 x^{2} + 5 x + 3) (3 x - 2) = 0

x = 3, x = - \frac{1}{2}, x = \frac{2}{3}

Decimal Notation

x = 3, x = - 0.5, x = 0.66666 \dots

Solution steps

(- 2 x^{2} + 5 x + 3) (3 x - 2) = 0

Factor

(- 2 x^{2} + 5 x + 3) (3 x - 2) : - (x - 3) (2 x + 1) (3 x - 2)

- (x - 3) (2 x + 1) (3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or 2 x + 1 = 0 or 3 x - 2 = 0

Solve

x - 3 = 0 : x = 3

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

The solutions are

x = 3, x = - \frac{1}{2}, x = \frac{2}{3}

0 = 6 x^{4} - 8 x^{3} + 1

(x + 1)^{3} (x - 1) = 0

0 = 12 x^{3} + 12 x^{2} - 24 x

0 = x (x^{2} - 3)

a^{6} = 58 + (6 - 1) - 7

What are the solutions to the equation (-2x^2+5x+3)(3x-2)=0 ?
The solutions to the equation (-2x^2+5x+3)(3x-2)=0 are x=3,x=-1/2 ,x= 2/3
Find the zeros of (-2x^2+5x+3)(3x-2)=0
The zeros of (-2x^2+5x+3)(3x-2)=0 are x=3,x=-1/2 ,x= 2/3