What are the solutions to the equation 64=w^3 ?

The solutions to the equation 64=w^3 are w=4,w=-2+2sqrt(3)i,w=-2-2sqrt(3)i

Find the zeros of 64=w^3

The zeros of 64=w^3 are w=4,w=-2+2sqrt(3)i,w=-2-2sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

64 = w^{3}

w = 4, w = - 2 + 23 i, w = - 2 - 23 i

Solution steps

64 = w^{3}

Switch sides

w^{3} = 64

For

x^{3} = f (a)

the solutions are

Simplify

w = 4, w = - 2 + 23 i, w = - 2 - 23 i

(x^{2} + 2) (x^{2} - 2) (x^{2} - 1) = 0

x^{6} + x^{4} - 10 x + 8 = 0

3 y^{3} - 23 y^{2} - 8 y = 0

x, x^{4} + y^{4} = 17

k^{3} = 216

What are the solutions to the equation 64=w^3 ?
The solutions to the equation 64=w^3 are w=4,w=-2+2sqrt(3)i,w=-2-2sqrt(3)i
Find the zeros of 64=w^3
The zeros of 64=w^3 are w=4,w=-2+2sqrt(3)i,w=-2-2sqrt(3)i