What are the solutions to the equation 5x^4-6x^3-2x^2=0 ?

The solutions to the equation 5x^4-6x^3-2x^2=0 are x=0,x=(3+sqrt(19))/5 ,x=(3-sqrt(19))/5

Find the zeros of 5x^4-6x^3-2x^2=0

The zeros of 5x^4-6x^3-2x^2=0 are x=0,x=(3+sqrt(19))/5 ,x=(3-sqrt(19))/5

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5 x^{4} - 6 x^{3} - 2 x^{2} = 0

x = 0, x = \frac{3 + 19}{5}, x = \frac{3 - 19}{5}

Decimal Notation

x = 0, x = 1.47177 \dots, x = - 0.27177 \dots

Solution steps

5 x^{4} - 6 x^{3} - 2 x^{2} = 0

Factor

5 x^{4} - 6 x^{3} - 2 x^{2} : x^{2} (5 x^{2} - 6 x - 2)

x^{2} (5 x^{2} - 6 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 5 x^{2} - 6 x - 2 = 0

Solve

5 x^{2} - 6 x - 2 = 0 : x = \frac{3 + 19}{5}, x = \frac{3 - 19}{5}

The solutions are

x = 0, x = \frac{3 + 19}{5}, x = \frac{3 - 19}{5}

x^{3} - 6 x^{2} + 15 x - 14 = 0

x^{3} = 1 + x + x^{2}

2 x^{3} - 2 x^{2} - 24 x = 0

y^{2} y^{2} + y + 32 = (y - 4)^{2}

3 x^{3} - 5 x^{2} + 6 x = 0

What are the solutions to the equation 5x^4-6x^3-2x^2=0 ?
The solutions to the equation 5x^4-6x^3-2x^2=0 are x=0,x=(3+sqrt(19))/5 ,x=(3-sqrt(19))/5
Find the zeros of 5x^4-6x^3-2x^2=0
The zeros of 5x^4-6x^3-2x^2=0 are x=0,x=(3+sqrt(19))/5 ,x=(3-sqrt(19))/5