What are the solutions to the equation 0=x^3-3x^2-5x+15 ?

The solutions to the equation 0=x^3-3x^2-5x+15 are x=3,x=-sqrt(5),x=sqrt(5)

Find the zeros of 0=x^3-3x^2-5x+15

The zeros of 0=x^3-3x^2-5x+15 are x=3,x=-sqrt(5),x=sqrt(5)

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0 = x^{3} - 3 x^{2} - 5 x + 15

x = 3, x = - 5, x = 5

Decimal Notation

x = 3, x = - 2.23606 \dots, x = 2.23606 \dots

Solution steps

0 = x^{3} - 3 x^{2} - 5 x + 15

Switch sides

x^{3} - 3 x^{2} - 5 x + 15 = 0

Factor

x^{3} - 3 x^{2} - 5 x + 15 : (x - 3) (x + 5) (x - 5)

(x - 3) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = 3, x = - 5, x = 5

x^{4} - 7 x^{3} + 10 x^{2} - 2 x + 4 = 0

k^{3} = - 1

(x^{2} - 9) (x^{3} - 8) = 0

x^{5} + 2 x - 1 = 0

15 x^{4} - 445 x^{2} + 8000 = 0

What are the solutions to the equation 0=x^3-3x^2-5x+15 ?
The solutions to the equation 0=x^3-3x^2-5x+15 are x=3,x=-sqrt(5),x=sqrt(5)
Find the zeros of 0=x^3-3x^2-5x+15
The zeros of 0=x^3-3x^2-5x+15 are x=3,x=-sqrt(5),x=sqrt(5)