What are the solutions to the equation (x^2-9)(x^3-8)=0 ?

The solutions to the equation (x^2-9)(x^3-8)=0 are x=-3,x=3,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of (x^2-9)(x^3-8)=0

The zeros of (x^2-9)(x^3-8)=0 are x=-3,x=3,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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(x^{2} - 9) (x^{3} - 8) = 0

x = - 3, x = 3, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

(x^{2} - 9) (x^{3} - 8) = 0

Factor

(x^{2} - 9) (x^{3} - 8) : (x + 3) (x - 3) (x - 2) (x^{2} + 2 x + 4)

(x + 3) (x - 3) (x - 2) (x^{2} + 2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 3 = 0 or x - 2 = 0 or x^{2} + 2 x + 4 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x + 4 = 0 : x = - 1 + 3 i, x = - 1 - 3 i

The solutions are

x = - 3, x = 3, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

x^{5} + 2 x - 1 = 0

15 x^{4} - 445 x^{2} + 8000 = 0

x^{3} + x - 1 = 1

6 m^{4} + m^{3} - 22 m^{2} - 11 m + 6 = 0

y^{4} - 13 y^{3} = - 42 y^{2}

What are the solutions to the equation (x^2-9)(x^3-8)=0 ?
The solutions to the equation (x^2-9)(x^3-8)=0 are x=-3,x=3,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of (x^2-9)(x^3-8)=0
The zeros of (x^2-9)(x^3-8)=0 are x=-3,x=3,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i