What are the solutions to the equation 6m^4+m^3-22m^2-11m+6=0 ?

The solutions to the equation 6m^4+m^3-22m^2-11m+6=0 are m=-1,m=2,m= 1/3 ,m=-3/2

Find the zeros of 6m^4+m^3-22m^2-11m+6=0

The zeros of 6m^4+m^3-22m^2-11m+6=0 are m=-1,m=2,m= 1/3 ,m=-3/2

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6 m^{4} + m^{3} - 22 m^{2} - 11 m + 6 = 0

m = - 1, m = 2, m = \frac{1}{3}, m = - \frac{3}{2}

Decimal Notation

m = - 1, m = 2, m = 0.33333 \dots, m = - 1.5

Solution steps

6 m^{4} + m^{3} - 22 m^{2} - 11 m + 6 = 0

Factor

6 m^{4} + m^{3} - 22 m^{2} - 11 m + 6 : (m + 1) (m - 2) (3 m - 1) (2 m + 3)

(m + 1) (m - 2) (3 m - 1) (2 m + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 1 = 0 or m - 2 = 0 or 3 m - 1 = 0 or 2 m + 3 = 0

Solve

m + 1 = 0 : m = - 1

Solve

m - 2 = 0 : m = 2

Solve

3 m - 1 = 0 : m = \frac{1}{3}

Solve

2 m + 3 = 0 : m = - \frac{3}{2}

The solutions are

m = - 1, m = 2, m = \frac{1}{3}, m = - \frac{3}{2}

y^{4} - 13 y^{3} = - 42 y^{2}

9 x = \frac{1}{4} x^{3}

- \frac{x ^{3}}{3} - x^{2} + 3 x + 10 = 0

(s^{2} + 17800 s + 39500000)^{2} = 0

t, (1 + t)^{5} = 1.2784

What are the solutions to the equation 6m^4+m^3-22m^2-11m+6=0 ?
The solutions to the equation 6m^4+m^3-22m^2-11m+6=0 are m=-1,m=2,m= 1/3 ,m=-3/2
Find the zeros of 6m^4+m^3-22m^2-11m+6=0
The zeros of 6m^4+m^3-22m^2-11m+6=0 are m=-1,m=2,m= 1/3 ,m=-3/2