What are the solutions to the equation 2n^3-n^2-136n=0 ?

The solutions to the equation 2n^3-n^2-136n=0 are n=0,n=-8,n= 17/2

Find the zeros of 2n^3-n^2-136n=0

The zeros of 2n^3-n^2-136n=0 are n=0,n=-8,n= 17/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 n^{3} - n^{2} - 136 n = 0

n = 0, n = - 8, n = \frac{17}{2}

Decimal Notation

n = 0, n = - 8, n = 8.5

Solution steps

2 n^{3} - n^{2} - 136 n = 0

Factor

2 n^{3} - n^{2} - 136 n : n (n + 8) (2 n - 17)

n (n + 8) (2 n - 17) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n = 0 or n + 8 = 0 or 2 n - 17 = 0

Solve

n + 8 = 0 : n = - 8

Solve

2 n - 17 = 0 : n = \frac{17}{2}

The solutions are

n = 0, n = - 8, n = \frac{17}{2}

6 x^{4} - 4 x^{2} + 2 = 0

1024 = r^{5}

3 x^{3} - 24 x^{2} + 54 x = 0

x^{3} - 2 x^{2} - 15 x + 36 = 0

r^{5} = 32

What are the solutions to the equation 2n^3-n^2-136n=0 ?
The solutions to the equation 2n^3-n^2-136n=0 are n=0,n=-8,n= 17/2
Find the zeros of 2n^3-n^2-136n=0
The zeros of 2n^3-n^2-136n=0 are n=0,n=-8,n= 17/2