What are the solutions to the equation x^3-2x^2-15x+36=0 ?

The solutions to the equation x^3-2x^2-15x+36=0 are x=3,x=-4

Find the zeros of x^3-2x^2-15x+36=0

The zeros of x^3-2x^2-15x+36=0 are x=3,x=-4

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x^{3} - 2 x^{2} - 15 x + 36 = 0

x = 3, x = - 4

Solution steps

x^{3} - 2 x^{2} - 15 x + 36 = 0

Factor

x^{3} - 2 x^{2} - 15 x + 36 : (x - 3)^{2} (x + 4)

(x - 3)^{2} (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 4 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 3, x = - 4

r^{5} = 32

8 x^{3} + 14 x^{2} - 5 x - 2 = 0

2 x^{4} + 9 x^{2} = 68

0 = 9 y - y^{3}

2.7 = (1 + x)^{6}

What are the solutions to the equation x^3-2x^2-15x+36=0 ?
The solutions to the equation x^3-2x^2-15x+36=0 are x=3,x=-4
Find the zeros of x^3-2x^2-15x+36=0
The zeros of x^3-2x^2-15x+36=0 are x=3,x=-4