What are the solutions to the equation 1=m^3 ?

The solutions to the equation 1=m^3 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i

Find the zeros of 1=m^3

The zeros of 1=m^3 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i

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1 = m^{3}

m = 1, m = - \frac{1}{2} + \frac{3}{2} i, m = - \frac{1}{2} - \frac{3}{2} i

Solution steps

1 = m^{3}

Switch sides

m^{3} = 1

For

x^{3} = f (a)

the solutions are

m = 1, m = \frac{- 1 + 3 i}{2}, m = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

m = 1, m = - \frac{1}{2} + \frac{3}{2} i, m = - \frac{1}{2} - \frac{3}{2} i

x^{4} - 8 x^{2} = 16

\frac{r ^{3}}{9} = 3

x^{4} = - 2 + 23 i

5 - x^{3} = x^{2} + 6

9 x^{3} - 54 x^{2} - x + 6 = 0

What are the solutions to the equation 1=m^3 ?
The solutions to the equation 1=m^3 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i
Find the zeros of 1=m^3
The zeros of 1=m^3 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i