What are the solutions to the equation x^3-4x^2-53x+168=0 ?

The solutions to the equation x^3-4x^2-53x+168=0 are x=3,x=-7,x=8

Find the zeros of x^3-4x^2-53x+168=0

The zeros of x^3-4x^2-53x+168=0 are x=3,x=-7,x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 4 x^{2} - 53 x + 168 = 0

x = 3, x = - 7, x = 8

Solution steps

x^{3} - 4 x^{2} - 53 x + 168 = 0

Factor

x^{3} - 4 x^{2} - 53 x + 168 : (x - 3) (x + 7) (x - 8)

(x - 3) (x + 7) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 7 = 0 or x - 8 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 7 = 0 : x = - 7

Solve

x - 8 = 0 : x = 8

The solutions are

x = 3, x = - 7, x = 8

x^{3} - 3 x = 1

x^{2 + 1} = 8

v^{3} = 8

m^{3} - 64 = 0

3^{3} = (9 x^{3})

What are the solutions to the equation x^3-4x^2-53x+168=0 ?
The solutions to the equation x^3-4x^2-53x+168=0 are x=3,x=-7,x=8
Find the zeros of x^3-4x^2-53x+168=0
The zeros of x^3-4x^2-53x+168=0 are x=3,x=-7,x=8