What are the solutions to the equation x^{2+1}=8 ?

The solutions to the equation x^{2+1}=8 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of x^{2+1}=8

The zeros of x^{2+1}=8 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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x^{2 + 1} = 8

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

x^{2 + 1} = 8

For

x^{3} = f (a)

the solutions are

Simplify

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

v^{3} = 8

m^{3} - 64 = 0

3^{3} = (9 x^{3})

x^{3} - 3 x = x

y, x = (y + 2)^{3}

What are the solutions to the equation x^{2+1}=8 ?
The solutions to the equation x^{2+1}=8 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of x^{2+1}=8
The zeros of x^{2+1}=8 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i