What are the solutions to the equation m^3-4m^2+4m=0 ?

The solutions to the equation m^3-4m^2+4m=0 are m=0,m=2

Find the zeros of m^3-4m^2+4m=0

The zeros of m^3-4m^2+4m=0 are m=0,m=2

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m^{3} - 4 m^{2} + 4 m = 0

m = 0, m = 2

Solution steps

m^{3} - 4 m^{2} + 4 m = 0

Factor

m^{3} - 4 m^{2} + 4 m : m (m - 2)^{2}

m (m - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m = 0 or m - 2 = 0

Solve

m - 2 = 0 : m = 2

The solutions are

m = 0, m = 2

0.024 = (1 + \frac{x}{12})^{12} - 1

x^{6} - 11 x^{3} + 30 = 0

x^{3} - 6 x^{2} - 7 x = 0

x^{4} - 5 x^{2} - 8 = 0

x^{5} (x + 1) (x - 1) = 0

What are the solutions to the equation m^3-4m^2+4m=0 ?
The solutions to the equation m^3-4m^2+4m=0 are m=0,m=2
Find the zeros of m^3-4m^2+4m=0
The zeros of m^3-4m^2+4m=0 are m=0,m=2