What are the solutions to the equation (2x-5)(2x-5)=0 ?

The solutions to the equation (2x-5)(2x-5)=0 are x= 5/2

Find the zeros of (2x-5)(2x-5)=0

The zeros of (2x-5)(2x-5)=0 are x= 5/2

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(2 x - 5) (2 x - 5) = 0

x = \frac{5}{2}

Solution steps

(2 x - 5) (2 x - 5) = 0

Simplify

(2 x - 5)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

2 x^{2} + 10 x = - 7

v^{2} + 4 v + 3

\frac{11}{6}

81 (3 p + 2 q)^{2} - 64 r^{2}

50 a^{3} - 32 a b^{4}

What are the solutions to the equation (2x-5)(2x-5)=0 ?
The solutions to the equation (2x-5)(2x-5)=0 are x= 5/2
Find the zeros of (2x-5)(2x-5)=0
The zeros of (2x-5)(2x-5)=0 are x= 5/2