What are the solutions to the equation 2x^2+10x=-7 ?

The solutions to the equation 2x^2+10x=-7 are x=(-5+sqrt(11))/2 ,x=-(5+sqrt(11))/2

Find the zeros of 2x^2+10x=-7

The zeros of 2x^2+10x=-7 are x=(-5+sqrt(11))/2 ,x=-(5+sqrt(11))/2

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2 x^{2} + 10 x = - 7

x = \frac{- 5 + 11}{2}, x = - \frac{5 + 11}{2}

Solution steps

2 x^{2} + 10 x = - 7

Move

7

to the left side

2 x^{2} + 10 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 7 = 211

x_{1, 2} = \frac{- 10 \pm 2 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2 11}{2 \cdot 2}, x_{2} = \frac{- 10 - 2 11}{2 \cdot 2}

x = \frac{- 10 + 2 11}{2 \cdot 2} : \frac{- 5 + 11}{2}

x = \frac{- 10 - 2 11}{2 \cdot 2} : - \frac{5 + 11}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 11}{2}, x = - \frac{5 + 11}{2}

v^{2} + 4 v + 3

\frac{11}{6}

81 (3 p + 2 q)^{2} - 64 r^{2}

50 a^{3} - 32 a b^{4}

4 a^{2} - 16 = 0

What are the solutions to the equation 2x^2+10x=-7 ?
The solutions to the equation 2x^2+10x=-7 are x=(-5+sqrt(11))/2 ,x=-(5+sqrt(11))/2
Find the zeros of 2x^2+10x=-7
The zeros of 2x^2+10x=-7 are x=(-5+sqrt(11))/2 ,x=-(5+sqrt(11))/2