What are the solutions to the equation 4a^2-16=0 ?

The solutions to the equation 4a^2-16=0 are a=2,a=-2

Find the zeros of 4a^2-16=0

The zeros of 4a^2-16=0 are a=2,a=-2

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4 a^{2} - 16 = 0

a = 2, a = - 2

Solution steps

4 a^{2} - 16 = 0

Move

16

to the right side

4 a^{2} = 16

Divide both sides by

4

a^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 4, a = - 4

4 = 2

- 4 = - 2

a = 2, a = - 2

1 2^{2} + x^{2} = 1 7^{2}

\frac{5 x - 2}{3} - \frac{2 - x}{3} > - 1

- \frac{5}{9} + (- \frac{7}{12})

0.2 5^{\frac{1}{3}}

x (x - 2) + 12 = (x + 1) (x + 2)

What are the solutions to the equation 4a^2-16=0 ?
The solutions to the equation 4a^2-16=0 are a=2,a=-2
Find the zeros of 4a^2-16=0
The zeros of 4a^2-16=0 are a=2,a=-2