What are the solutions to the equation (x+1)^3-6(x+1)-4=0 ?

The solutions to the equation (x+1)^3-6(x+1)-4=0 are x=-3,x=-sqrt(3),x=sqrt(3)

Find the zeros of (x+1)^3-6(x+1)-4=0

The zeros of (x+1)^3-6(x+1)-4=0 are x=-3,x=-sqrt(3),x=sqrt(3)

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(x + 1)^{3} - 6 (x + 1) - 4 = 0

x = - 3, x = - 3, x = 3

Decimal Notation

x = - 3, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

(x + 1)^{3} - 6 (x + 1) - 4 = 0

Expand

(x + 1)^{3} - 6 (x + 1) - 4 : x^{3} + 3 x^{2} - 3 x - 9

x^{3} + 3 x^{2} - 3 x - 9 = 0

Factor

x^{3} + 3 x^{2} - 3 x - 9 : (x + 3) (x + 3) (x - 3)

(x + 3) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 3, x = - 3, x = 3

x^{4} - a x^{2} + b = 0

Z^{56} = 498

y, x = 8 y^{3}

4 x^{3} - 2 x^{2} + x + 7 = 0

- x^{5} + 16 x = 0

What are the solutions to the equation (x+1)^3-6(x+1)-4=0 ?
The solutions to the equation (x+1)^3-6(x+1)-4=0 are x=-3,x=-sqrt(3),x=sqrt(3)
Find the zeros of (x+1)^3-6(x+1)-4=0
The zeros of (x+1)^3-6(x+1)-4=0 are x=-3,x=-sqrt(3),x=sqrt(3)