What are the solutions to the equation x^2(x+5)-12(x+3)=0 ?

The solutions to the equation x^2(x+5)-12(x+3)=0 are x=-2,x=3,x=-6

Find the zeros of x^2(x+5)-12(x+3)=0

The zeros of x^2(x+5)-12(x+3)=0 are x=-2,x=3,x=-6

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x^{2} (x + 5) - 12 (x + 3) = 0

x = - 2, x = 3, x = - 6

Solution steps

x^{2} (x + 5) - 12 (x + 3) = 0

Factor

x^{2} (x + 5) - 12 (x + 3) : (x + 2) (x - 3) (x + 6)

(x + 2) (x - 3) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 3 = 0 or x + 6 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

Solve

x + 6 = 0 : x = - 6

The solutions are

x = - 2, x = 3, x = - 6

x^{4} - 8 x^{2} - 33 = 0

- x^{3} + x^{2} + x = 0

t, f d^{2} + 3 = t^{3}

15 (3 x - 2)^{4} = 15

- λ^{3} + 2 λ^{2} + λ - 2 = 0

What are the solutions to the equation x^2(x+5)-12(x+3)=0 ?
The solutions to the equation x^2(x+5)-12(x+3)=0 are x=-2,x=3,x=-6
Find the zeros of x^2(x+5)-12(x+3)=0
The zeros of x^2(x+5)-12(x+3)=0 are x=-2,x=3,x=-6