What are the solutions to the equation 2x^3-9x^2-6x+5=0 ?

The solutions to the equation 2x^3-9x^2-6x+5=0 are x=-1,x= 1/2 ,x=5

Find the zeros of 2x^3-9x^2-6x+5=0

The zeros of 2x^3-9x^2-6x+5=0 are x=-1,x= 1/2 ,x=5

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2 x^{3} - 9 x^{2} - 6 x + 5 = 0

x = - 1, x = \frac{1}{2}, x = 5

Decimal Notation

x = - 1, x = 0.5, x = 5

Solution steps

2 x^{3} - 9 x^{2} - 6 x + 5 = 0

Factor

2 x^{3} - 9 x^{2} - 6 x + 5 : (x + 1) (2 x - 1) (x - 5)

(x + 1) (2 x - 1) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x - 1 = 0 or x - 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 1, x = \frac{1}{2}, x = 5

x^{4} - 9 x^{2} + 11 x - 2 = 0

3 x^{3} - x - 2 = 0

b^{3} + 3.31 = 0.41

30 x^{3} + 5 x^{2} - 25 x = 0

x, V = 2 x^{3} - 3 y^{3}

What are the solutions to the equation 2x^3-9x^2-6x+5=0 ?
The solutions to the equation 2x^3-9x^2-6x+5=0 are x=-1,x= 1/2 ,x=5
Find the zeros of 2x^3-9x^2-6x+5=0
The zeros of 2x^3-9x^2-6x+5=0 are x=-1,x= 1/2 ,x=5