What are the solutions to the equation 2x^2x^4x^4=512 ?

The solutions to the equation 2x^2x^4x^4=512 are x=\sqrt[10]{256},x=-\sqrt[10]{256}

Find the zeros of 2x^2x^4x^4=512

The zeros of 2x^2x^4x^4=512 are x=\sqrt[10]{256},x=-\sqrt[10]{256}

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2 x^{2} x^{4} x^{4} = 512

Decimal Notation

x = 1.74110 \dots, x = - 1.74110 \dots

Solution steps

2 x^{2} x^{4} x^{4} = 512

Simplify

2 x^{10} = 512

Divide both sides by

2

\frac{2 x ^{10}}{2} = \frac{512}{2}

x^{10} = 256

For

x^{n} = f (a)

, n is even, the solutions are

(x - 4)^{3} = (\frac{1}{8})^{- 1}

(x - 2) (x + 3) (x - 5) = 0

x^{5} - 10 x^{3} + 9 x = 0

p^{6} = 6

x^{4} + 3 x - 4 = 0

What are the solutions to the equation 2x^2x^4x^4=512 ?
The solutions to the equation 2x^2x^4x^4=512 are x=\sqrt[10]{256},x=-\sqrt[10]{256}
Find the zeros of 2x^2x^4x^4=512
The zeros of 2x^2x^4x^4=512 are x=\sqrt[10]{256},x=-\sqrt[10]{256}