What are the solutions to the equation -a^3+5a^2-8a+4=0 ?

The solutions to the equation -a^3+5a^2-8a+4=0 are a=1,a=2

Find the zeros of -a^3+5a^2-8a+4=0

The zeros of -a^3+5a^2-8a+4=0 are a=1,a=2

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- a^{3} + 5 a^{2} - 8 a + 4 = 0

a = 1, a = 2

Solution steps

- a^{3} + 5 a^{2} - 8 a + 4 = 0

Factor

- a^{3} + 5 a^{2} - 8 a + 4 : - (a - 1) (a - 2)^{2}

- (a - 1) (a - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a - 1 = 0 or a - 2 = 0

Solve

a - 1 = 0 : a = 1

Solve

a - 2 = 0 : a = 2

The solutions are

a = 1, a = 2

x^{6} + 3 x^{3} = 40

36 x^{3} - 49 x = 0

z^{5} = - 32 + 0 i

x^{3} + x^{2} = 12

x^{3} - 3 = 53 x + 2

What are the solutions to the equation -a^3+5a^2-8a+4=0 ?
The solutions to the equation -a^3+5a^2-8a+4=0 are a=1,a=2
Find the zeros of -a^3+5a^2-8a+4=0
The zeros of -a^3+5a^2-8a+4=0 are a=1,a=2