What is the answer to (x-7)^2=x^2+4x+13 ?

The answer to (x-7)^2=x^2+4x+13 is x=2

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(x-7)^2=x^2+4x+13

(x - 7)^{2} = x^{2} + 4 x + 13

x = 2

Solution steps

(x - 7)^{2} = x^{2} + 4 x + 13

Expand

(x - 7)^{2} : x^{2} - 14 x + 49

x^{2} - 14 x + 49 = x^{2} + 4 x + 13

Move

49

to the right side

x^{2} - 14 x = x^{2} + 4 x - 36

Subtract

x^{2} + 4 x

from both sides

x^{2} - 14 x - (x^{2} + 4 x) = x^{2} + 4 x - 36 - (x^{2} + 4 x)

Simplify

- 18 x = - 36

Divide both sides by

- 18

x = 2

6 x > 42

\frac{5 \cdot ( 3 ^{2} \cdot 10 ) ^{2}}{3 ^{2} \cdot 6 0 ^{2}}

5 x^{2} = 6 x + 27

\frac{12 !}{10 ! ( 12 - 10 ) !}

x^{2} - x y + x - x y^{2} + y^{3} - y^{2}

What is the answer to (x-7)^2=x^2+4x+13 ?
The answer to (x-7)^2=x^2+4x+13 is x=2
Solve for x: (x-7)^2=x^2+4x+13
The solution is x=2