What are the solutions to the equation 0=2x^3-3x ?

The solutions to the equation 0=2x^3-3x are x=0,x=-sqrt(3/2),x=sqrt(3/2)

Find the zeros of 0=2x^3-3x

The zeros of 0=2x^3-3x are x=0,x=-sqrt(3/2),x=sqrt(3/2)

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0 = 2 x^{3} - 3 x

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = 0, x = - 1.22474 \dots, x = 1.22474 \dots

Solution steps

0 = 2 x^{3} - 3 x

Switch sides

2 x^{3} - 3 x = 0

Factor

2 x^{3} - 3 x : x (2 x + 3) (2 x - 3)

x (2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 3 = 0 or 2 x - 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

18 x^{3} - 6 x^{2} - 16 x + 8 = 0

x^{4} + 2 x^{3} - 8 x^{2} - 18 x - 9 = 0

x^{3} + 91 x + 90 = 0

- x^{3} + 2 x^{2} + 4 x - 4 = 0

x^{3} - 10 x^{2} + 20 x = 26

What are the solutions to the equation 0=2x^3-3x ?
The solutions to the equation 0=2x^3-3x are x=0,x=-sqrt(3/2),x=sqrt(3/2)
Find the zeros of 0=2x^3-3x
The zeros of 0=2x^3-3x are x=0,x=-sqrt(3/2),x=sqrt(3/2)