What are the solutions to the equation 5x^3+4x=0 ?

The solutions to the equation 5x^3+4x=0 are x=0,x= 2/(sqrt(5))i,x=-2/(sqrt(5))i

Find the zeros of 5x^3+4x=0

The zeros of 5x^3+4x=0 are x=0,x= 2/(sqrt(5))i,x=-2/(sqrt(5))i

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5 x^{3} + 4 x = 0

x = 0, x = \frac{2}{5} i, x = - \frac{2}{5} i

Solution steps

5 x^{3} + 4 x = 0

Factor

5 x^{3} + 4 x : x (5 x^{2} + 4)

x (5 x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 5 x^{2} + 4 = 0

Solve

5 x^{2} + 4 = 0 : x = \frac{2}{5} i, x = - \frac{2}{5} i

The solutions are

x = 0, x = \frac{2}{5} i, x = - \frac{2}{5} i

2 x^{4} - 2 x^{2} - 4 = 0

x^{6} = 16 x^{4}

x^{4} - 6 x^{3} + 33 x^{2} + 6 x - 34 = 0

z^{3} = \frac{125}{216}

4 x^{3} - 12 x^{2} - 16 x = 0

What are the solutions to the equation 5x^3+4x=0 ?
The solutions to the equation 5x^3+4x=0 are x=0,x= 2/(sqrt(5))i,x=-2/(sqrt(5))i
Find the zeros of 5x^3+4x=0
The zeros of 5x^3+4x=0 are x=0,x= 2/(sqrt(5))i,x=-2/(sqrt(5))i