What are the solutions to the equation (sqrt(6)x-1)(x^2+1)=0 ?

The solutions to the equation (sqrt(6)x-1)(x^2+1)=0 are x= 1/(sqrt(6)),x=i,x=-i

Find the zeros of (sqrt(6)x-1)(x^2+1)=0

The zeros of (sqrt(6)x-1)(x^2+1)=0 are x= 1/(sqrt(6)),x=i,x=-i

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(6 x - 1) (x^{2} + 1) = 0

x = \frac{1}{6}, x = i, x = - i

Solution steps

(6 x - 1) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 x - 1 = 0 or x^{2} + 1 = 0

Solve

6 x - 1 = 0 : x = \frac{1}{6}

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = \frac{1}{6}, x = i, x = - i

48 = 3 r^{4}

x, 8 x^{3} + 4 y = 32

x^{3} + 8 = \frac{9 x ^{3}}{2}

x^{2} 5 x + 2 = - 4

(x) = \frac{x ^{3} + x - 1}{2}

What are the solutions to the equation (sqrt(6)x-1)(x^2+1)=0 ?
The solutions to the equation (sqrt(6)x-1)(x^2+1)=0 are x= 1/(sqrt(6)),x=i,x=-i
Find the zeros of (sqrt(6)x-1)(x^2+1)=0
The zeros of (sqrt(6)x-1)(x^2+1)=0 are x= 1/(sqrt(6)),x=i,x=-i