What are the solutions to the equation 3x^3+x^2-130x-168=0 ?

The solutions to the equation 3x^3+x^2-130x-168=0 are x=-6,x=-4/3 ,x=7

Find the zeros of 3x^3+x^2-130x-168=0

The zeros of 3x^3+x^2-130x-168=0 are x=-6,x=-4/3 ,x=7

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3 x^{3} + x^{2} - 130 x - 168 = 0

x = - 6, x = - \frac{4}{3}, x = 7

Decimal Notation

x = - 6, x = - 1.33333 \dots, x = 7

Solution steps

3 x^{3} + x^{2} - 130 x - 168 = 0

Factor

3 x^{3} + x^{2} - 130 x - 168 : (x + 6) (3 x + 4) (x - 7)

(x + 6) (3 x + 4) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or 3 x + 4 = 0 or x - 7 = 0

Solve

x + 6 = 0 : x = - 6

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

x - 7 = 0 : x = 7

The solutions are

x = - 6, x = - \frac{4}{3}, x = 7

(x + 2) (x^{2} + 6 x + 10) = 0

(2 x - 1)^{3} - 4 x (2 x - 3) = 5

a, a^{5} 4^{- 2} = 2

y^{3} = - 64

x^{3} = 243

What are the solutions to the equation 3x^3+x^2-130x-168=0 ?
The solutions to the equation 3x^3+x^2-130x-168=0 are x=-6,x=-4/3 ,x=7
Find the zeros of 3x^3+x^2-130x-168=0
The zeros of 3x^3+x^2-130x-168=0 are x=-6,x=-4/3 ,x=7