What are the solutions to the equation 288=24x^{12} ?

The solutions to the equation 288=24x^{12} are

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288=24x^{12}

288 = 24 x^{12}

Solution steps

288 = 24 x^{12}

Switch sides

24 x^{12} = 288

Divide both sides by

24

x^{12} = 12

Rewrite the equation with

u = x^{2}

and

u^{6} = x^{12}

u^{6} = 12

Solve

Substitute back

u = x^{2},

solve for

x

Solve

The solutions are

- x^{3} + 15 x^{2} - 75 x + 125 = 0

x, y^{2} = 2 x^{3}

8 1^{2} = b^{3}

- x^{3} + 30 x^{2} - 279 x + 810 = 0

x^{4} - 4 x^{3} + 14 x^{2} - 4 x + 13 = 0

What are the solutions to the equation 288=24x^{12} ?
The solutions to the equation 288=24x^{12} are
Find the zeros of 288=24x^{12}
The zeros of 288=24x^{12} are