What are the solutions to the equation 100(1+r)^4=84 ?

The solutions to the equation 100(1+r)^4=84 are r=\sqrt[4]{21/25}-1,r=-\sqrt[4]{21/25}-1

Find the zeros of 100(1+r)^4=84

The zeros of 100(1+r)^4=84 are r=\sqrt[4]{21/25}-1,r=-\sqrt[4]{21/25}-1

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100 (1 + r)^{4} = 84

Decimal Notation

r = - 0.04265 \dots, r = - 1.95734 \dots

Solution steps

100 (1 + r)^{4} = 84

Divide both sides by

100

(1 + r)^{4} = \frac{21}{25}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

8 x^{3} + 6 x^{2} - 3 x - 1 = 0

x^{6} - x^{3} = 2

- x^{3} + 3 = 0

(2 - x)^{3} - (2 - x) = 0

x^{4} - x^{3} - 6 x^{2} + 4 x + 8 = 0

What are the solutions to the equation 100(1+r)^4=84 ?
The solutions to the equation 100(1+r)^4=84 are r=\sqrt[4]{21/25}-1,r=-\sqrt[4]{21/25}-1
Find the zeros of 100(1+r)^4=84
The zeros of 100(1+r)^4=84 are r=\sqrt[4]{21/25}-1,r=-\sqrt[4]{21/25}-1