What are the solutions to the equation x^4-x^3-6x^2+4x+8=0 ?

The solutions to the equation x^4-x^3-6x^2+4x+8=0 are x=-1,x=2,x=-2

Find the zeros of x^4-x^3-6x^2+4x+8=0

The zeros of x^4-x^3-6x^2+4x+8=0 are x=-1,x=2,x=-2

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x^{4} - x^{3} - 6 x^{2} + 4 x + 8 = 0

x = - 1, x = 2, x = - 2

Solution steps

x^{4} - x^{3} - 6 x^{2} + 4 x + 8 = 0

Factor

x^{4} - x^{3} - 6 x^{2} + 4 x + 8 : (x + 1) (x - 2)^{2} (x + 2)

(x + 1) (x - 2)^{2} (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0 or x + 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

Solve

x + 2 = 0 : x = - 2

The solutions are

x = - 1, x = 2, x = - 2

3 x^{3} - 5 x^{2} + 2 x = 0

x, 0 = 324 x^{3} - 144 x y

z^{3} - 27 i = 0

3 x^{4} - 5 x^{3} + 2 x - 1 = 0

b^{4} - 2 = 1

What are the solutions to the equation x^4-x^3-6x^2+4x+8=0 ?
The solutions to the equation x^4-x^3-6x^2+4x+8=0 are x=-1,x=2,x=-2
Find the zeros of x^4-x^3-6x^2+4x+8=0
The zeros of x^4-x^3-6x^2+4x+8=0 are x=-1,x=2,x=-2