What are the solutions to the equation 1180=1000(1+x)^6 ?

The solutions to the equation 1180=1000(1+x)^6 are x=\sqrt[6]{59/50}-1,x=-\sqrt[6]{59/50}-1

Find the zeros of 1180=1000(1+x)^6

The zeros of 1180=1000(1+x)^6 are x=\sqrt[6]{59/50}-1,x=-\sqrt[6]{59/50}-1

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1180 = 1000 (1 + x)^{6}

Decimal Notation

x = 0.02796 \dots, x = - 2.02796 \dots

Solution steps

1180 = 1000 (1 + x)^{6}

Switch sides

1000 (1 + x)^{6} = 1180

Divide both sides by

1000

(1 + x)^{6} = \frac{59}{50}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

0 = x^{4} + 4 x^{3} + 2 x^{2} - 5 x - 2

65 = b^{5}

3 x^{3} - 30 x^{2} + 63 x = 0

x^{4} - 25 x + 144 = 0

(2 - x) \cdot (2 - x) \cdot (4 - x) = 0

What are the solutions to the equation 1180=1000(1+x)^6 ?
The solutions to the equation 1180=1000(1+x)^6 are x=\sqrt[6]{59/50}-1,x=-\sqrt[6]{59/50}-1
Find the zeros of 1180=1000(1+x)^6
The zeros of 1180=1000(1+x)^6 are x=\sqrt[6]{59/50}-1,x=-\sqrt[6]{59/50}-1