What are the solutions to the equation x^3-22x-24=0 ?

The solutions to the equation x^3-22x-24=0 are x=-4,x=2+sqrt(10),x=2-sqrt(10)

Find the zeros of x^3-22x-24=0

The zeros of x^3-22x-24=0 are x=-4,x=2+sqrt(10),x=2-sqrt(10)

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x^{3} - 22 x - 24 = 0

x = - 4, x = 2 + 10, x = 2 - 10

Decimal Notation

x = - 4, x = 5.16227 \dots, x = - 1.16227 \dots

Solution steps

x^{3} - 22 x - 24 = 0

Factor

x^{3} - 22 x - 24 : (x + 4) (x^{2} - 4 x - 6)

(x + 4) (x^{2} - 4 x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x^{2} - 4 x - 6 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x^{2} - 4 x - 6 = 0 : x = 2 + 10, x = 2 - 10

The solutions are

x = - 4, x = 2 + 10, x = 2 - 10

k^{5} - 3 k^{3} + 3 k^{2} - 9 = 16

0.1296 = a^{4}

(x^{2} - 2) (5 x + 3) = 0

12 x^{3} + 12 x^{2} + 12 x = 0

x^{3} - 7 x^{2} + 8 x - 2 = 0

What are the solutions to the equation x^3-22x-24=0 ?
The solutions to the equation x^3-22x-24=0 are x=-4,x=2+sqrt(10),x=2-sqrt(10)
Find the zeros of x^3-22x-24=0
The zeros of x^3-22x-24=0 are x=-4,x=2+sqrt(10),x=2-sqrt(10)