What are the solutions to the equation (x^2-4)(x-2)=0 ?

The solutions to the equation (x^2-4)(x-2)=0 are x=2,x=-2

Find the zeros of (x^2-4)(x-2)=0

The zeros of (x^2-4)(x-2)=0 are x=2,x=-2

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(x^{2} - 4) (x - 2) = 0

x = 2, x = - 2

Solution steps

(x^{2} - 4) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} - 4 = 0 or x - 2 = 0

Solve

x^{2} - 4 = 0 : x = 2, x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 2, x = - 2

x^{3} + 2 x^{2} = - x

n^{3} - n - 6 = 0

2 x^{4} + 5 = 0

x^{4} - \frac{1}{4} - 18750 x^{2} = 0

z^{3} = 4

What are the solutions to the equation (x^2-4)(x-2)=0 ?
The solutions to the equation (x^2-4)(x-2)=0 are x=2,x=-2
Find the zeros of (x^2-4)(x-2)=0
The zeros of (x^2-4)(x-2)=0 are x=2,x=-2