What are the solutions to the equation n^3-n-6=0 ?

The solutions to the equation n^3-n-6=0 are n=2,n=-1+sqrt(2)i,n=-1-sqrt(2)i

Find the zeros of n^3-n-6=0

The zeros of n^3-n-6=0 are n=2,n=-1+sqrt(2)i,n=-1-sqrt(2)i

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n^{3} - n - 6 = 0

n = 2, n = - 1 + 2 i, n = - 1 - 2 i

Solution steps

n^{3} - n - 6 = 0

Factor

n^{3} - n - 6 : (n - 2) (n^{2} + 2 n + 3)

(n - 2) (n^{2} + 2 n + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n - 2 = 0 or n^{2} + 2 n + 3 = 0

Solve

n - 2 = 0 : n = 2

Solve

n^{2} + 2 n + 3 = 0 : n = - 1 + 2 i, n = - 1 - 2 i

The solutions are

n = 2, n = - 1 + 2 i, n = - 1 - 2 i

2 x^{4} + 5 = 0

x^{4} - \frac{1}{4} - 18750 x^{2} = 0

z^{3} = 4

z^{3} = 0

\frac{x ^{3}}{i} - 27 = 0

What are the solutions to the equation n^3-n-6=0 ?
The solutions to the equation n^3-n-6=0 are n=2,n=-1+sqrt(2)i,n=-1-sqrt(2)i
Find the zeros of n^3-n-6=0
The zeros of n^3-n-6=0 are n=2,n=-1+sqrt(2)i,n=-1-sqrt(2)i