What are the solutions to the equation (x^3)/i-27=0 ?

The solutions to the equation (x^3)/i-27=0 are x=(3sqrt(3))/2+i 3/2 ,x=-(3sqrt(3))/2+i 3/2 ,x=-3i

Find the zeros of (x^3)/i-27=0

The zeros of (x^3)/i-27=0 are x=(3sqrt(3))/2+i 3/2 ,x=-(3sqrt(3))/2+i 3/2 ,x=-3i

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\frac{x ^{3}}{i} - 27 = 0

x = \frac{3 3}{2} + i \frac{3}{2}, x = - \frac{3 3}{2} + i \frac{3}{2}, x = - 3 i

Solution steps

\frac{x ^{3}}{i} - 27 = 0

Move

27

to the right side

\frac{x ^{3}}{i} = 27

Multiply both sides by

i

x^{3} = 27 i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 3, a = 27 i

∣ a ∣ = 27

ar g (a) = \frac{π}{2}

Simplify

x = \frac{3 3}{2} + i \frac{3}{2}, x = - \frac{3 3}{2} + i \frac{3}{2}, x = - 3 i

x^{2} (5 x - 7) (3 x + 2) = 0

3 x^{3} + 4 x^{2} = 15 x

x^{3} - 3 x^{2} - 9 x + 21 = 0

t^{3} = 30

x^{4} - 2 x^{3} + 5 x - 1 = 0

What are the solutions to the equation (x^3)/i-27=0 ?
The solutions to the equation (x^3)/i-27=0 are x=(3sqrt(3))/2+i 3/2 ,x=-(3sqrt(3))/2+i 3/2 ,x=-3i
Find the zeros of (x^3)/i-27=0
The zeros of (x^3)/i-27=0 are x=(3sqrt(3))/2+i 3/2 ,x=-(3sqrt(3))/2+i 3/2 ,x=-3i