What are the solutions to the equation y^3-4y=0 ?

The solutions to the equation y^3-4y=0 are y=0,y=-2,y=2

Find the zeros of y^3-4y=0

The zeros of y^3-4y=0 are y=0,y=-2,y=2

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y^{3} - 4 y = 0

y = 0, y = - 2, y = 2

Solution steps

y^{3} - 4 y = 0

Factor

y^{3} - 4 y : y (y + 2) (y - 2)

y (y + 2) (y - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y + 2 = 0 or y - 2 = 0

Solve

y + 2 = 0 : y = - 2

Solve

y - 2 = 0 : y = 2

The solutions are

y = 0, y = - 2, y = 2

z^{4} = 3 - 3 i

x^{4} - 3 x^{2} - 2 x - 59 = 0

c^{11} = - 1 - \frac{c}{2}

3 x^{6} + x^{3} (2 x^{3} - 1) = 4

(r^{2} + 2 r + 10) 3 r (r + 1) 2 = 0

What are the solutions to the equation y^3-4y=0 ?
The solutions to the equation y^3-4y=0 are y=0,y=-2,y=2
Find the zeros of y^3-4y=0
The zeros of y^3-4y=0 are y=0,y=-2,y=2