What are the solutions to the equation 5x^4-15=1-25x-110 ?

The solutions to the equation 5x^4-15=1-25x-110 are No Solution for x\in\mathbb{R}

Find the zeros of 5x^4-15=1-25x-110

The zeros of 5x^4-15=1-25x-110 are No Solution for x\in\mathbb{R}

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5 x^{4} - 15 = 1 - 25 x - 110

No Solution for x \in R

Solution steps

5 x^{4} - 15 = 1 - 25 x - 110

Refine

5 x^{4} - 15 = - 25 x - 109

Move

109

to the left side

5 x^{4} + 94 = - 25 x

Move

25 x

to the left side

5 x^{4} + 94 + 25 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

5 x^{4} + 25 x + 94 = 0

Find one solution for

5 x^{4} + 25 x + 94 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

12 + x^{3} = 4 x^{2} + 12

x^{6} = 1 0^{24}

7 y^{3} + 25 y^{2} = 12 y

8 x - 6 x^{2} - 2 x^{3} = 0

(x + 3) (x - 1) (x - 2) = 96

What are the solutions to the equation 5x^4-15=1-25x-110 ?
The solutions to the equation 5x^4-15=1-25x-110 are No Solution for x\in\mathbb{R}
Find the zeros of 5x^4-15=1-25x-110
The zeros of 5x^4-15=1-25x-110 are No Solution for x\in\mathbb{R}