What are the solutions to the equation 7y^3+25y^2=12y ?

The solutions to the equation 7y^3+25y^2=12y are y=0,y= 3/7 ,y=-4

Find the zeros of 7y^3+25y^2=12y

The zeros of 7y^3+25y^2=12y are y=0,y= 3/7 ,y=-4

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7 y^{3} + 25 y^{2} = 12 y

y = 0, y = \frac{3}{7}, y = - 4

Decimal

y = 0, y = 0.42857 \dots, y = - 4

Solution steps

7 y^{3} + 25 y^{2} = 12 y

Move

12 y

to the left side

7 y^{3} + 25 y^{2} - 12 y = 0

Factor

7 y^{3} + 25 y^{2} - 12 y : y (7 y - 3) (y + 4)

y (7 y - 3) (y + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 7 y - 3 = 0 or y + 4 = 0

Solve

7 y - 3 = 0 : y = \frac{3}{7}

Solve

y + 4 = 0 : y = - 4

The solutions are

y = 0, y = \frac{3}{7}, y = - 4

8 x - 6 x^{2} - 2 x^{3} = 0

(x + 3) (x - 1) (x - 2) = 96

a^{3} = 0

3 (t^{2} - 9)^{2} + 22 (t^{2} - 9) = - 7

3 (x + 7)^{3} = 648

What are the solutions to the equation 7y^3+25y^2=12y ?
The solutions to the equation 7y^3+25y^2=12y are y=0,y= 3/7 ,y=-4
Find the zeros of 7y^3+25y^2=12y
The zeros of 7y^3+25y^2=12y are y=0,y= 3/7 ,y=-4