What is factor t^2+t-12 ?

The solution to factor t^2+t-12 is (t-3)(t+4)

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factor t^2+t-12

factor

t^{2} + t - 12

(t - 3) (t + 4)

Solution steps

t^{2} + t - 12

Break the expression into groups

= (t^{2} - 3 t) + (4 t - 12)

Factor out

t

from

t^{2} - 3 t : t (t - 3)

Factor out

4

from

4 t - 12 : 4 (t - 3)

= t (t - 3) + 4 (t - 3)

Factor out common term

t - 3

= (t - 3) (t + 4)

5 ∣ x - 4 ∣ + 6 \leq 26

6 \cdot (\frac{1}{3})^{1}

25 c + 10 c^{2} = 0

1.06 x - 2 \leq 0.544

5 x - 40 > 2 (2 + 8 x)