What are the solutions to the equation 2x^3-6x^2-7x-4=0 ?

The solutions to the equation 2x^3-6x^2-7x-4=0 are x=4,x=-1/2+i 1/2 ,x=-1/2-i 1/2

Find the zeros of 2x^3-6x^2-7x-4=0

The zeros of 2x^3-6x^2-7x-4=0 are x=4,x=-1/2+i 1/2 ,x=-1/2-i 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{3} - 6 x^{2} - 7 x - 4 = 0

x = 4, x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

Solution steps

2 x^{3} - 6 x^{2} - 7 x - 4 = 0

Factor

2 x^{3} - 6 x^{2} - 7 x - 4 : (x - 4) (2 x^{2} + 2 x + 1)

(x - 4) (2 x^{2} + 2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or 2 x^{2} + 2 x + 1 = 0

Solve

x - 4 = 0 : x = 4

Solve

2 x^{2} + 2 x + 1 = 0 : x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

The solutions are

x = 4, x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

5 x^{2} (x^{2} - 3) = 0

(r - 4)^{2} (r + 8) = 0

x^{3} - 9 x - 1 = 0

x^{(3)} + 3 x^{(2)} - 4 x - 12 = 0

4 x^{4} - 5 x^{2} - 9 = 0

What are the solutions to the equation 2x^3-6x^2-7x-4=0 ?
The solutions to the equation 2x^3-6x^2-7x-4=0 are x=4,x=-1/2+i 1/2 ,x=-1/2-i 1/2
Find the zeros of 2x^3-6x^2-7x-4=0
The zeros of 2x^3-6x^2-7x-4=0 are x=4,x=-1/2+i 1/2 ,x=-1/2-i 1/2