What are the solutions to the equation 2x^3-3x^2-9x=0 ?

The solutions to the equation 2x^3-3x^2-9x=0 are x=0,x=-3/2 ,x=3

Find the zeros of 2x^3-3x^2-9x=0

The zeros of 2x^3-3x^2-9x=0 are x=0,x=-3/2 ,x=3

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2 x^{3} - 3 x^{2} - 9 x = 0

x = 0, x = - \frac{3}{2}, x = 3

Decimal Notation

x = 0, x = - 1.5, x = 3

Solution steps

2 x^{3} - 3 x^{2} - 9 x = 0

Factor

2 x^{3} - 3 x^{2} - 9 x : x (2 x + 3) (x - 3)

x (2 x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 3 = 0 or x - 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - \frac{3}{2}, x = 3

64 x^{3} = 8

d^{3} - 1 = 0

6 x^{4} + 29 x^{2} + 28 = 0

x^{2} (x^{4} - 9) = 8 x^{4}

7 (z^{2} - 3 z - 4) (z + 7) = 0

What are the solutions to the equation 2x^3-3x^2-9x=0 ?
The solutions to the equation 2x^3-3x^2-9x=0 are x=0,x=-3/2 ,x=3
Find the zeros of 2x^3-3x^2-9x=0
The zeros of 2x^3-3x^2-9x=0 are x=0,x=-3/2 ,x=3